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9a^2/3a=3
We move all terms to the left:
9a^2/3a-(3)=0
Domain of the equation: 3a!=0We multiply all the terms by the denominator
a!=0/3
a!=0
a∈R
9a^2-3*3a=0
Wy multiply elements
9a^2-9a=0
a = 9; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·9·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*9}=\frac{0}{18} =0 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*9}=\frac{18}{18} =1 $
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